\(\int (3+3 \sin (e+f x))^2 \, dx\) [438]

Optimal result

Integrand size = 12, antiderivative size = 36 \[ \int (3+3 \sin (e+f x))^2 \, dx=\frac {27 x}{2}-\frac {18 \cos (e+f x)}{f}-\frac {9 \cos (e+f x) \sin (e+f x)}{2 f} \]

[Out]

3/2*a^2*x-2*a^2*cos(f*x+e)/f-1/2*a^2*cos(f*x+e)*sin(f*x+e)/f

Rubi [A] (verified)

Time = 0.01 (sec) , antiderivative size = 45, normalized size of antiderivative = 1.25, number of steps used = 1, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.083, Rules used = {2723} \[ \int (3+3 \sin (e+f x))^2 \, dx=-\frac {2 a^2 \cos (e+f x)}{f}-\frac {a^2 \sin (e+f x) \cos (e+f x)}{2 f}+\frac {3 a^2 x}{2} \]

[In]

Int[(a + a*Sin[e + f*x])^2,x]

[Out]

(3*a^2*x)/2 - (2*a^2*Cos[e + f*x])/f - (a^2*Cos[e + f*x]*Sin[e + f*x])/(2*f)

Rule 2723

Int[((a_) + (b_.)*sin[(c_.) + (d_.)*(x_)])^2, x_Symbol] :> Simp[(2*a^2 + b^2)*(x/2), x] + (-Simp[2*a*b*(Cos[c
+ d*x]/d), x] - Simp[b^2*Cos[c + d*x]*(Sin[c + d*x]/(2*d)), x]) /; FreeQ[{a, b, c, d}, x]

Rubi steps \begin{align*} \text {integral}& = \frac {3 a^2 x}{2}-\frac {2 a^2 \cos (e+f x)}{f}-\frac {a^2 \cos (e+f x) \sin (e+f x)}{2 f} \\ \end{align*}

Mathematica [A] (verified)

Time = 0.08 (sec) , antiderivative size = 32, normalized size of antiderivative = 0.89 \[ \int (3+3 \sin (e+f x))^2 \, dx=-\frac {9 (-2 (e+3 f x)+8 \cos (e+f x)+\sin (2 (e+f x)))}{4 f} \]

[In]

Integrate[(3 + 3*Sin[e + f*x])^2,x]

[Out]

(-9*(-2*(e + 3*f*x) + 8*Cos[e + f*x] + Sin[2*(e + f*x)]))/(4*f)

Maple [A] (verified)

Time = 0.50 (sec) , antiderivative size = 32, normalized size of antiderivative = 0.89

method	result	size
parallelrisch	\(-\frac {a^{2} \left (-6 f x +8 \cos \left (f x +e \right )+\sin \left (2 f x +2 e \right )-8\right )}{4 f}\)	\(32\)
risch	\(\frac {3 a^{2} x}{2}-\frac {2 a^{2} \cos \left (f x +e \right )}{f}-\frac {a^{2} \sin \left (2 f x +2 e \right )}{4 f}\)	\(39\)
parts	\(a^{2} x +\frac {a^{2} \left (-\frac {\sin \left (f x +e \right ) \cos \left (f x +e \right )}{2}+\frac {f x}{2}+\frac {e}{2}\right )}{f}-\frac {2 a^{2} \cos \left (f x +e \right )}{f}\)	\(50\)
derivativedivides	\(\frac {a^{2} \left (-\frac {\sin \left (f x +e \right ) \cos \left (f x +e \right )}{2}+\frac {f x}{2}+\frac {e}{2}\right )-2 \cos \left (f x +e \right ) a^{2}+\left (f x +e \right ) a^{2}}{f}\)	\(52\)
default	\(\frac {a^{2} \left (-\frac {\sin \left (f x +e \right ) \cos \left (f x +e \right )}{2}+\frac {f x}{2}+\frac {e}{2}\right )-2 \cos \left (f x +e \right ) a^{2}+\left (f x +e \right ) a^{2}}{f}\)	\(52\)
norman	\(\frac {\frac {a^{2} \left (\tan ^{3}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{f}+\frac {4 a^{2} \left (\tan ^{4}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{f}+\frac {3 a^{2} x}{2}-\frac {a^{2} \tan \left (\frac {f x}{2}+\frac {e}{2}\right )}{f}+3 a^{2} x \left (\tan ^{2}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )+\frac {3 a^{2} x \left (\tan ^{4}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{2}+\frac {4 a^{2} \left (\tan ^{2}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{f}}{\left (1+\tan ^{2}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )^{2}}\)	\(131\)

[In]

int((a+a*sin(f*x+e))^2,x,method=_RETURNVERBOSE)

[Out]

-1/4*a^2*(-6*f*x+8*cos(f*x+e)+sin(2*f*x+2*e)-8)/f

Fricas [A] (verification not implemented)

none

Time = 0.28 (sec) , antiderivative size = 41, normalized size of antiderivative = 1.14 \[ \int (3+3 \sin (e+f x))^2 \, dx=\frac {3 \, a^{2} f x - a^{2} \cos \left (f x + e\right ) \sin \left (f x + e\right ) - 4 \, a^{2} \cos \left (f x + e\right )}{2 \, f} \]

[In]

integrate((a+a*sin(f*x+e))^2,x, algorithm="fricas")

[Out]

1/2*(3*a^2*f*x - a^2*cos(f*x + e)*sin(f*x + e) - 4*a^2*cos(f*x + e))/f

Sympy [A] (verification not implemented)

Time = 0.10 (sec) , antiderivative size = 78, normalized size of antiderivative = 2.17 \[ \int (3+3 \sin (e+f x))^2 \, dx=\begin {cases} \frac {a^{2} x \sin ^{2}{\left (e + f x \right )}}{2} + \frac {a^{2} x \cos ^{2}{\left (e + f x \right )}}{2} + a^{2} x - \frac {a^{2} \sin {\left (e + f x \right )} \cos {\left (e + f x \right )}}{2 f} - \frac {2 a^{2} \cos {\left (e + f x \right )}}{f} & \text {for}\: f \neq 0 \\x \left (a \sin {\left (e \right )} + a\right )^{2} & \text {otherwise} \end {cases} \]

[In]

integrate((a+a*sin(f*x+e))**2,x)

[Out]

Piecewise((a**2*x*sin(e + f*x)**2/2 + a**2*x*cos(e + f*x)**2/2 + a**2*x - a**2*sin(e + f*x)*cos(e + f*x)/(2*f)
- 2*a**2*cos(e + f*x)/f, Ne(f, 0)), (x*(a*sin(e) + a)**2, True))

Maxima [F(-1)]

Timed out. \[ \int (3+3 \sin (e+f x))^2 \, dx=\text {Timed out} \]

[In]

integrate((a+a*sin(f*x+e))^2,x, algorithm="maxima")

[Out]

Timed out

Giac [A] (verification not implemented)

none

Time = 0.44 (sec) , antiderivative size = 38, normalized size of antiderivative = 1.06 \[ \int (3+3 \sin (e+f x))^2 \, dx=\frac {3}{2} \, a^{2} x - \frac {2 \, a^{2} \cos \left (f x + e\right )}{f} - \frac {a^{2} \sin \left (2 \, f x + 2 \, e\right )}{4 \, f} \]

[In]

integrate((a+a*sin(f*x+e))^2,x, algorithm="giac")

[Out]

3/2*a^2*x - 2*a^2*cos(f*x + e)/f - 1/4*a^2*sin(2*f*x + 2*e)/f

Mupad [B] (verification not implemented)

Time = 6.91 (sec) , antiderivative size = 123, normalized size of antiderivative = 3.42 \[ \int (3+3 \sin (e+f x))^2 \, dx=\frac {3\,a^2\,x}{2}-\frac {a^2\,\left (\frac {3\,e}{2}+\frac {3\,f\,x}{2}\right )-a^2\,{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^3-a^2\,\left (\frac {3\,e}{2}+\frac {3\,f\,x}{2}-4\right )+a^2\,\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )+{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^2\,\left (2\,a^2\,\left (\frac {3\,e}{2}+\frac {3\,f\,x}{2}\right )-a^2\,\left (3\,e+3\,f\,x-4\right )\right )}{f\,{\left ({\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^2+1\right )}^2} \]

[In]

int((a + a*sin(e + f*x))^2,x)

[Out]

(3*a^2*x)/2 - (a^2*((3*e)/2 + (3*f*x)/2) - a^2*tan(e/2 + (f*x)/2)^3 - a^2*((3*e)/2 + (3*f*x)/2 - 4) + a^2*tan(
e/2 + (f*x)/2) + tan(e/2 + (f*x)/2)^2*(2*a^2*((3*e)/2 + (3*f*x)/2) - a^2*(3*e + 3*f*x - 4)))/(f*(tan(e/2 + (f*
x)/2)^2 + 1)^2)